Question

find the amount in rupees 1000 Rate% per annum 5% Time in years 3

Answer 1

SOLUTION :

Principal(P) = Rs 1000       (given)

Rate of Interest(R) = 5% per annum      (given)

Time(T) = 3 years     (given)

To be found :-

Amount(A)

We know that

Amount(A) = Simple Interest(S.I) + Principal(P)

We have to find Simple Interest(S.I)

$S.I = \frac{P \times R\times T}{100}$

$S.I = \frac{1000 \times 5 \times 3}{100}$

$S.I = Rs 150$

∴ Simple Interest(S.I) = rs 150

Now,

Amount(A) = Simple Interest(S.I) + Principal(P)

Amount(A) = Rs 150 + Rs 1000

Amount(A) = Rs 1150

Hence

Amount(A) is Rs 1150

Answer 2

Answer:

1157.62

Step-by-step explanation:

A = P[1 + R/100]^n