Question

Find the amount of ₹1000 in 2 yrs at 10% per annum, when the intrest is compounded annually​

Answer 1

Step-by-step explanation:

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Answer 2

$\huge \bf{{\color{indigo}{a}}{\color{maroon}{n}}{\red{s}}}$

Here ,principle = 1000

R = 10 per annum

n = 2 years

$\therefore \: amount \: after \: 2 \: yrs \: = \: ( 1 + \frac{r}{200}</strong><strong>$

$= rs.1000 \times ( 1 + \frac{10}{200})$

$(1 + \frac{1}{20}) = rs1000 \times ( \frac{21}{20})$

$= rs1000 \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} = rs.1215.50$

Hence, compound interest = amount principle

= Rs. 1215.50 - Rs. 1000 = rs 215.50