Question

Find the amount of 31.250 at 12% pa compounded annually for 2 years 6 months. Also, find the compound interest.​

Answer 1

Answer:

Rs.41552

Step-by-step explanation:

$sol {}^{n}$

Here P=31,250 R= 12 Time n= 2years and 6months

= 2years and 1/2 years

Let the amount be 'x´

So,

$x = p(1 + \frac{r}{100} ) {}^{2} (1 + \frac{1}{2} \times r \frac{1}{100} )$

$x = 31250 \times (1 + \frac{12}{100} ) {}^{2} (1 + \frac{ \frac{12}{2} }{100} )$

$x = 31250 \times ( \frac{112}{100} ) {}^{2} (1 + \frac{6}{100} )$

$x = 31250 \times \frac{112}{100} \times \frac{112}{100} \times \frac{106}{100}$

$x = 41552$