Question

Find the amount of 36000 after2 years at compound interest. If r1= 10% and r2=12%

Answer 1

Answer:

Step-by-step explanation:

P=36000

T=2yrs

R1=10% R2=12%

So A=P(1+r1/100)(1+r2/100)

=>A=36000*1+10/100*1+12/100

=>A=36000*11/10*112/100

=>A=44352

CI=A-P

=44352-36000

=8352

Answer 2

36000(1+10/100)(1+12/100)
(36000×110×112)/10000
36×11×112
a= 44352
ci=44352-36000
ci=8352rs