Question

find the amount of ammonium chloride that will separate out when 155g of its solution is 333K is cooled to 293K

Answer 1

a) Potassium nitrate is least soluble in water at 293 K. 
b) Potassium nitrate shows maximum change in its solubility at 333 K. 
c) Amount of ammonium chloride that will separate out when 155 g of its solution at 333 K is cooled to 293 K = 155 g - 137 g = 18 g 
d) The solubility of a salt increases with increase in temperature.
e) Mass of NaCl that would be needed to make a saturated solution in 10 g of water at 293 K = 360/100 = 3.6 g