Find the amount of benzoic acid is to be dissolved in water to get 500g of 30% of aqueous solution ? explanation is must.No spammers or Google answers
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Number of moles of benzoic acid required=0.15×250/1000=0.0375 moles
Molar mass of benzoic acid=7(12)+6(1)+2(16) = 84+6+32=122 g/mol
Mass of benzoic acid required=122×0.0375 =4.575 g
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