Question

find the amount of co2 liberated from the combustion of ethane
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Answer 1

Explanation:

While the Hydrocarbon is Ethane , x=2 and y=6 . So 1 mol of Ethane will evolve 2 moles of CO2, ie, 30 gms of ethane will evolve 2*22.4 l of CO2 at STP, so for 150 gms it is 2*5*22.4= 224 l of CO2. Carbon dioxidedissociates by the following reaction 2CO2=2CO+O2...

Answer 2

Answer:

While the Hydrocarbon is Ethane , x=2 and y=6 . So 1 mol of Ethane will evolve 2 moles of CO2, ie, 30 gms of ethane will evolve 2*22.4 l of CO2 at STP, so for 150 gms it is 2*5*22.4= 224 l of CO2. Carbon dioxide dissociates by the following reaction 2CO2=2CO+O2.