Question

find the amount of compound interest to 15000 for 3 year at 10% per annum compounded annually​

Answer 1

Answer:

Here, P = ₹ 15000, n = 3 years, r = 10% p. a.

We need to find: C. I.

Now, by compound interest formula:

$\because \: A = P(1 + \frac{r}{100} )^{n} \\ \therefore \: A = 15000 \times (1 + \frac{10}{100} )^{3} \\ \therefore \: A = 15000 \times (1 + \frac{1}{10} )^{3} \\ \therefore \: A = 15000 \times (\frac{10 + 1}{10} )^{3} \\ \therefore \: A = 15000 \times (\frac{11}{10} )^{3} \\ \therefore \: A = 15000 \times \frac{1331}{1000} \\ \therefore \: A = 15 \times 1331 \\ \therefore \: A = 19965 \\ now \\ compound \: interest \: (c.i.) = A - P \\ = 19965 - 15000 = 4965$

Thus, the compound interest C. I. = ₹4965

Answer 2

Answer:

Hope you get the answer