find the amount of ethylene required to produce 1 mole of ethyl alcohol
Answers
Answered by
0
Answer:
The molar masses of ethylene and ethyl alcohol are 28 g/mol and 46 g/mol respectively.
1 mole (28 g) of ethylene gives 1 mole (46 g) of ethanol.
Hence, the theoretical yield is 9.6×2846=15.77.
The percentage yield is 4615.77×100=29.8%.
HOPE ITS HELPFUL BUDDY....
Similar questions