find the amount of flowof current when 5ohm,8ohm and 12ohm of resistors connected to three dry cells with 2volt each
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Answer:
6/25 A
Explanation:
R1=5ohm
R2=8ohm
R3=12ohm
V=3*2=6v
I=?
Rs=R1+R2+R3
=5+8+12=25ohm
V=IR
I=V/R
I=6/25 A
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