find the amount of heat energy utilised to convert 10grams of ice at-5 degree c to 10grams of steam at 100degree c given specific heat of ice= 0.5cal/g degree c
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step1:-ice goes to -5degree to 0 degree
H1 =msdT=10gm.0.5cal/gdegree c. (0+5)c
=25cal
step 2:-now ice convert into water
H2=mLf =10gm.80cal/gm
=800cal
step 3;-water goes to 0degree to 100
H3=mSdT=10gm.1cal/g degree.c. (100-0)
=1000cal
step4:-water convert into stream
H4=mLv=10gm.540cal/g=5400cal
now add all heat H1+H2+H3+H4=(25+800+1000+5400)cal
=7225cal
H1 =msdT=10gm.0.5cal/gdegree c. (0+5)c
=25cal
step 2:-now ice convert into water
H2=mLf =10gm.80cal/gm
=800cal
step 3;-water goes to 0degree to 100
H3=mSdT=10gm.1cal/g degree.c. (100-0)
=1000cal
step4:-water convert into stream
H4=mLv=10gm.540cal/g=5400cal
now add all heat H1+H2+H3+H4=(25+800+1000+5400)cal
=7225cal
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