Question

Find the amount of heat required to convert 100
g of water at 100°C into steam at 100°C. Latent
heat of vaporization of water is 540 cal g!​

Answer 1

Answer:

Explanation:

Given: m = 150g

L = 540 cal/g

To find: Q = ?

Formula: Q = mL

Solution: Q = 150 × 540

= 81000 cal

Heat energy needed is 81000 cal.