Find the amount of heat required to convert 10g of water at 100 degrees into steam
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Heat required =−10
0
C ice to 0
0
C ice + 0
0
C ice to 0
0
C water + 0
0
C water to 100
0
C water + 100
0
C water to 100
0
C steam
=10[0.487(10)+80+1(100−0)+536]
=7208.7cal [since specific heat of ice=0.487cal/g-K]
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