Question

Find the amount of Rs. 5000 in 2 years at 10% per annum compound interest.
​

Answer 1

${\huge{\boxed{\sf{\pink{Answer}}}}}$

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year.

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50.

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yr

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.= 1050.

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.= 1050.So 5000 * x = 1050

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.= 1050.So 5000 * x = 1050x = 1050/5000 = 0.21

${\huge{\boxed{\sf{\pink{Answer}}}}}$5000 * 10% = 500 for 1st year. In the same way for 2nd year it would be 500 and c.I of 500 is 50. So the total C.I is Rs = 1050.The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.= 1050.So 5000 * x = 1050x = 1050/5000 = 0.21x = 0.21 * 100 = 21%.

${\huge{\boxed{\sf{\pink{hope \: its \: help \: u}}}}}$