Math, asked by Ashwinsanthosh8190, 1 year ago

Find the amount of Rs.8000 for 2 years compounded annually and the rates being 9% per annum during the first year and the rate being 10% per annum during the second year

Answers

Answered by kalpsheladiya
100

Answer:

RS 9592

Step-by-step explanation:

P = RS 8000

R1= 9% pa

R2=10% pa

T = 2 years

A = P(1+R1/100)(1+R2/100)

= 8000(1+9/100)(1+10/100)

= 8000×109/100×11/10

= 8×109×11

= RS 9592.

Answered by windyyork
35

Amount would be Rs. 9592 for 2 years.

Step-by-step explanation:

Since we have given that

Principal = Rs. 8000

Time = 2 years

Rate of interest  for the first year = 9% p.a.

Rate of interest for the second year = 10% p.a.

According to question, we get that

A=P(1+\dfrac{r_1}{100})(1+\dfrac{r_2}{100})\\\\A=8000(1+\dfrac{9}{100})(1+\dfrac{10}{100})\\\\A=8000(1+0.09)(1+0.1)\\\\A=8000(1.09)(1.1)\\\\A=9592

Hence, Amount would be Rs. 9592 for 2 years.

# learn more:

Find the amount of ₹ 8000 for 2 years compounded annually and the rates being for 9 % per annum during the first year and 10 % per annum during the second year​

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