find the amount of the compound interest on rupees 10000 for 2 years at 6% per annum
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Step-by-step explanation:
given :
find the amount of the compound interest on rupees 10000 for 2 years at 6% per annum
to find :
find the amount of the compound interest on rupees
solution :
- Here P₁ = Rs.10000 and r = = 6%
- So, Amount after 1 year
- = ""P"(1 + "r"/100) =
- = `10000(1 + 6/100)`
- = `10000 xx (106)/(100)` = 10600 Thus, P2 = Rs.10600 and r = = 6%
- So, Amount after 2 year = ""P"(1 + "r"/100)
- = 10600(1 + 6/100)`
- = '10600 xx (106)/(100)` = 11236
- Thus, principle for the next 6 months =
- Rs.11236
- Interest for the next 6 months
- = `(11236 xx 6 xx 6)/(100 xx 12)
- = 337.08
- View in app X
- Therefore, amount after 1`(1)/(2)` years
- = Rs.11236 + Rs.337.08
- - Pc 11572.08
- So, Amount after 2 year
- = "P"(1 + "r"/100)`
- = '10600(1 + 6/100)`
- = `10600 xx (106)/(100) = 11236
- Thus, principle for the next 6 months
- Rs.11236
- Interest for the next 6 months
- = `(11236 xx 6 xx 6)/(100 xx 12)
- = 337.08
- Therefore, amount after 1 (1)/(2)` years
- = Rs.11236 + Rs.337.08
- = Rs.11573.08
- And Cl
- = A - P
- = Rs.11573.08 - Rs.10000
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