Question

find the amount of urea dissolved in 90g of water so that the vapour pressure drops from 400 mm to 350mm of hg?​

Answer 1

Explanation:

According to raoult's law,

p

0

p

0

−p

=

m×W

w×M

Where,

p

0

is Vapour pressure of pure water

p is vapour pressure of solvent

w is weight of solute

m is molecular weight of solute

W is molecular weight of solvent

32

32−31.84

=

m×200

10×18

⇒m=

0.005

0.9

=180