Question

Find the amount of water displaced by a solid ball of diameter 28 cm​

Answer 1

Given :-

Diameter of ball = d= 28 cm

To Find :-

Amount of water displaced

Solution :-

As we Know that ball can remove the water only the amount of its volume.

$\blue{ \mathtt {\: Volume \: of \: ball = \frac{4}{3} \pi {r}^{3} }}$

• Radius of ball = 28/2 = 14 cm

$\blue{ \mathtt {\: Volume \: of \: ball = \frac{4}{3} \times \frac{22}{7} \times {14}^{3} }}$

$\blue{ \mathtt {\: Volume \: of \: ball = \frac{4}{3} \times \frac{22}{7} \times {14}^{3} }}$

$\blue{ \mathtt {\: Volume \: of \: ball = 11498.66 \: \: {cm}^{3} }}$

$\blue{ \mathtt {\: Amount \: of \: water \: displaced = 11498.66 \: \: {cm}^{3} }}$

Or

$\blue{ \mathtt {\: Amount \: of \: water \: displaced = 11.5\: \: liter \: \: approx }}$

• Note
• $\tt{ \orange{ \: 1 \: liter \: = 1000 {cm}^{3} }}$

Answer 2

$\huge\mathfrak{✰ Solution}$

• We have found that 11498.66 cm3 cm of water is displaced by a spherical ball of diameter 28 cm and 0.004851 m3 of water is displaced by a spherical ball of the diameter of 0.21 m.