Question

find the amount of water displaced by a solid sperical ball of diameter 42cm.​

Answer 1

Step-by-step explanation:

Correct option is

A

38.808 cm

3

The amount of water displaced by a solid spherical ball when it is completely immersed in water is equal to its volume.

Volume of a sphere of radius r is

3

4

πr

3

As the diameter of the ball is 4.2 cm, its radius r=2.1 cm

Hence, volume of water displaced =

3

4

πr

3

=

3

4

×

7

22

×2.1×2.1×2.1=38.808 cm

3

Answer 2

Answer:

38808cm³

Step-by-step explanation:

volume displaced = volume of ball (Archimedes principle)

thus vol of ball = 4/3πr3

d = 42cm, thus r = 21cm.

thus 4/3*21*21*21*22/7

= 88*21*21

= 38808 cm³

thus water displaced = 38808cm³