find the amount of water displaced by a solid spherical ball of diameter is 28 CM
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Answered by
14
solution:
(i) Given:
Diameter of the spherical ball (d)= 28 cm
Radius =d/2= 28/2 cm = 14 cm
Amount of water displaced by a solid spherical ball = Volume of spherical ball =
4/3πr³
= (4/3 × 22/7 × 14 × 14 × 14)
= 34496/3 = 11498.67 cm³
Amount of water displaced by a solid spherical ball= 11498.67
cm³.
Hope it helps you
Answered by
5
Given :
Diameter of solid spherical ball (d)= 28 cm
To find :
The amount of water displaced by solid spherical ball
Solution :
Radius (r) = d/2 = 28/2 cm = 14 cm
Amount of water displaced by solid spherical ball = Volume of spherical ball =4/3 πr^3
=(4/3 × 22/7 × 14 × 14 × 14 )
=34496/3
=11498.67 cm^3
Answer : The amount of water displaced by solid spherical ball is 11498.67 cm^3.
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