Question

Find the amount of water displaced by a solid spherical ball of diameter:
(i) 28 cm
(ii) 0.21m.

Answer 1

Answer:

(i)The amount of water displaced by a solid spherical ball = 11,498.66 $cm^{3}$.

(ii)The amount of water displaced by a solid spherical ball = 0.004851 $cm^{3}$  

Step-by-step explanation:

the amount of water displaced by a solid spherical ball = volume of the spherical ball  

as volume of sphere = $\frac{4}{3}\pi r^{3}$

(i) given diameter = 28 cm

    now, d = 2r

           ⇒ r = $\frac{d}{2}$

           ⇒ r = $\frac{28}{2}$

           ⇒ r = 14 cm

∴ the amount of water displaced by a solid spherical ball = $\frac{4}{3}\pi r^{3}$

      = $\frac{4}{3}\pi \left ( 14 \right )^{3}$         ∵( π = 22/7 )

      =  11,498.66 $cm^{3}$

(ii) given diameter = 0.21 cm

    now, d = 2r

           ⇒ r = $\frac{d}{2}$

           ⇒ r = $\frac{0.21}{2}$

           ⇒ r = 0.105cm

∴ the amount of water displaced by a solid spherical ball = $\frac{4}{3}\pi r^{3}$

      = $\frac{4}{3}\pi \left ( 0.105 \right )^{3}$     ∵( π = 22/7 )

      =  0.004851 $cm^{3}$

Answer 2

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