Question

find the amount of water displaced by a solid spherical ball of diameter (i) 28cm (ii) 0.21m

Answer 1

AMOUNT OF WATER DISPLACED = VOLUME OF SPHERICAL BALL

I WILL USE THIS SYMBOL § FOR PIE VALUE

VOLUME OF SPHERICAL BALL= 4/3 * § R^3

= 4/3 * 22/7 * 14*14*14
=4/3 * 22*2*14*14
=11498.6667
HENCE THE VOLUME DISPLACED IS 11498.6667 cm^3

Answer 2

Amount of water displaced is also the volume of the sphere

$i)4 \div 3\pi {r}^{3} \\ 4 \div 3 \times 22 \div 7 \times 28 \times 28 \times 28 \\ 91989.333 {cm}^{3} \\ ii)4 \div 3\pi {r}^{3} \\ 4 \div 3 \times 22 \div 7 \times 0.21 \times 0.21 \times 0.21 \\ 0.038808 {m}^{3}$
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