Math, asked by adriano2213, 1 year ago

Find the amount of water displaced by a solid spherical ball of diameter 28cm

Answers

Answered by sindhug1612
9

Radius=14cm

Amount of water displaced = volume of the sphere

volume \: ofsphere =  \frac{4}{3} \pi {r}^{3}

=4/3×22/7×14×14×14

=11498.666 cm cube

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Answered by saif188
3

Answer:

The amount of water displaced by a solid spherical ball will be 11498.66cm^3 (approx.)

Step-by-step explanation:

radius, \: r \:  =  \:  \frac{d}{2}  =  \frac{28}{2}  = 14cm \\ volume \: of \: spherical \: ball =  \:  \frac{4}{3}\pi {r}^{3}  \\  =  \:  \frac{4}{3} \times  \frac{22}{7} \times 14 \times 14 \times 14 \\  =  \frac{34496}{3}  \\  =  \: 11498.66 {cm}^{3} (approx.)

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