Question

Find the amount of work done in moving a 5C charge from point A at 6 volts to a point B at 16 volts

Answer 1

Answer:-

w = 50 joule

Given :-

Q = 5c

$p_A = 6v , p_B = 16 v$

To find:-

The total work done.

Solution:-

Let the amount of work done to move the charge from potential A to potential B be W.

Now,

Net potential difference = $P_B - P_A$

→$P = 16 - 6$

→$p = 10 v$

Then,

$\huge \boxed{v = \dfrac{w}{q}}$

Put the given value,

→$10 = \dfrac{w}{5}$

→$w = 50 j$

hence,

The work done to bring the charge from 16 v to 6 v is 50 j.