Find the amount of work done in rotating an electric dipole, of dipole moment
3 x 10^-8 Cm, from its position of stable equilibrium to the position of unstable
equilibrium, in a uniform electric field of intensity 10^2 N/C.
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Answer:
follow the steps
Explanation:
Formual,
W=PE(1−cosθ)
=2PE ∵θ=180→cosθ=−1
=2×3×10
−8
×10
3
=6×10
5
J
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