Physics, asked by aayushboyka, 6 months ago

Find the amount of work done in rotating an electric dipole, of dipole moment

3 x 10^-8 Cm, from its position of stable equilibrium to the position of unstable

equilibrium, in a uniform electric field of intensity 10^2 N/C.

Answers

Answered by tushardubey257
0

Answer:

follow the steps

Explanation:

Formual,

W=PE(1−cosθ)

=2PE ∵θ=180→cosθ=−1

=2×3×10

−8

×10

3

=6×10

5

J

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