find the amount of work done in rotating electric dipole of dipole moment 3.2 into 10 to power minus 8 coulomb metre from its position of stable equilibrium to the position of unstable equilibrium in a uniform electric field of intensity 10 to the power 4 Newton Law
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dipole moment=3.2×10^-8
intensity=10^4 Newton
the statable equibrium(thera1)=0°
the unstateble equibrium(theta2)180°
workdone=P×E(cos0°-cos180°)
= 3.2×(10^-8)×(10^4(1-(-1)))
= 3.2×10^-8+4×2
=6.4×10^-4 J
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Lakhan I have no idea where it says
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