Physics, asked by manishpradeepkumarsh, 10 months ago

find the amount of work done in rotating electric dipole of dipole moment 3.2 into 10 to power minus 8 coulomb metre from its position of stable equilibrium to the position of unstable equilibrium in a uniform electric field of intensity 10 to the power 4 Newton Law

Answers

Answered by avantiraj999
3

dipole moment=3.2×10^-8

intensity=10^4 Newton

the statable equibrium(thera1)=0°

the unstateble equibrium(theta2)180°

workdone=P×E(cos0°-cos180°)

= 3.2×(10^-8)×(10^4(1-(-1)))

= 3.2×10^-8+4×2

=6.4×10^-4 J

Answered by rakhiabhi28
0

Answer:

Lakhan I have no idea where it says

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