Question

Find the amount on Rs 1200 taken for 2 years at 4% p.a. compounded quarterly.​

Answer 1

Given :-

• Principal = Rs. 1200
• Time = 2 years
• Rate = 4%

To find :-

• Amount

Knowledge Required :-

• Formula to calculate Amount :-

• Amount = P[1 + r/100]ⁿ

where,

• P = Principal
• r = rate
• n = time

Solution :-

Amount :-

→ Amount = P[1 + r/100]ⁿ

→ Amount = 1200[1 + 4/100]²

→ Amount = 1200[1 + 2/50]²

→ Amount = 1200[1 + 1/25]²

→ Amount = 1200[(25 + 1)/25]²

→ Amount = 1200[26/25]²

→ Amount = 1200 × 26/25 × 26/25

→ Amount = 1,297.92

★ Amount = Rs. 1,297.92

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Know MorE :-

• C.I. = Amount - Principal
• C.I. = P[1 + r/100]ⁿ - P
• S.I. = (P × R × T)/100
• Amount = Principal + Simple Interest

Answer 2

Given :

• Principal (P) = Rs.1200
• Time period (t) = 2 years
• Rate (R) = 4%

To Find :

• Amount

Formula Applied :

$\displaystyle{\underline{\boxed{\sf Amount = P\Big(1+\dfrac{r}{100}\Big)^t}}}$

Solution :

$\implies\sf P\Big(1+\dfrac{r}{100}\Big)^t$

$\implies \sf 1200\Big(1+\dfrac{4}{100}\Big)^2$

$\implies \sf 1200\Big(\dfrac{100+4}{100}\Big)^2$

$\implies \sf 1200\Big(\dfrac{104}{100}\Big)^2$

$\implies \sf 1200\Big(\dfrac{104\times 104}{100 \times 100}\Big)$

$\implies \sf 12{\cancel{0}}{\cancel{0}}\Big(\dfrac{10816}{100{\cancel{0}}{\cancel{0}}}\Big)$

$\implies \sf \dfrac{12 \times 10816}{100}$

$\implies \sf \dfrac{129792}{100}$

$\implies \sf Rs. 1297.92$

Required Answer :

Amount of the given condition is$\underline{ \sf Rs. 1297.92}$