Find the amount on Rs 500 for 2 years at 10% p.a. compounded annually
Answers
Step-by-step explanation:
EXPLANATION.
\sf \implies \lim_{\Delta x \to 0} \dfrac{(x + \Delta x)^{2} - 2(x + \Delta x)+ 1 - (x^{2}- 2x + 1) }{\Delta x}⟹lim
Δx→0
Δx
(x+Δx)
2
−2(x+Δx)+1−(x
2
−2x+1)
As we know that,
First we can put the value of Δx in equation,
And check in which form the equation is.
\sf \implies \lim_{\Delta x \to 0} \dfrac{(x + 0)^{2} - 2(x + 0)+ 1 - (x^{2}- 2x + 1) }{0}.⟹lim
Δx→0
0
(x+0)
2
−2(x+0)+1−(x
2
−2x+1)
.
\sf \implies \lim_{\Delta x \to 0} \dfrac{(x)^{2} - 2x+ 1 - x^{2}+ 2x - 1) }{0}.⟹lim
Δx→0
0
(x)
2
−2x+1−x
2
+2x−1)
.
\sf \implies \lim_{\Delta x \to 0} \dfrac{0}{0}.⟹lim
Δx→0
0
0
.
As we can see it is in the form of 0/0,
We can simply equate (factorizes) this equation, we get.
\sf \implies \lim_{\Delta x \to 0} \dfrac{(x^{2} + \Delta x^{2} + 2x\Delta x ) + (- 2x - 2 \Delta x) + 1 - (x^{2} - 2x + 1)}{\Delta x}.⟹lim
Δx→0
Δx
(x
2
+Δx
2
+2xΔx)+(−2x−2Δx)+1−(x
2
−2x+1)
.
\sf \implies \lim_{\Delta x \to 0} \dfrac{x^{2} + 2x \Delta x + \Delta x^{2} - 2x - 2 \Delta x + 1 - x^{2} + 2x - 1}{\Delta x}.⟹lim
Δx→0
Δx
x
2
+2xΔx+Δx
2
−2x−2Δx+1−x
2
+2x−1
.
\sf \implies \lim_{\Delta x \to 0} \dfrac{2x \Delta x + \Delta x^{2} - 2 \Delta x}{\Delta x}.⟹lim
Δx→0
Δx
2xΔx+Δx
2
−2Δx
.
\sf \implies \lim_{\Delta x \to 0} \dfrac{\Delta x(2x + \Delta x - 2)}{\Delta x}.⟹lim
Δx→0
Δx
Δx(2x+Δx−2)
.
Put the value of Δx = 0 in equation, we get.
\sf \implies \lim_{\Delta x \to 0} 2x + 0 - 2.⟹lim
Δx→0
2x+0−2.
\sf \implies \lim_{\Delta x \to 0} 2x - 2.⟹lim
Δx→0
2x−2.
\sf \implies \lim_{\Delta x \to 0} \dfrac{(x + \Delta x)^{2} - 2(x + \Delta x)+ 1 - (x^{2}- 2x + 1) }{\Delta x} = 2x - 2.⟹lim
Δx→0
Δx
(x+Δx)
2
−2(x+Δx)+1−(x
2
−2x+1)
=2x−2.
Answer = (2x - 2).
Answer:
Step-by-step explanation:
Given
Principle = 500
Time = 2 yrs
Rate of interest = 10%
Have to find amount
