find the amount on Rs1000 at rate of 8%pa .For 1½ years when intrest is compounded half yearly
Answers
Answer:
Principal (P)
=
R
s
.
1000
Rate (R)
=
8
%
p.a
Period (T)
=
1
1
2
years
=
3 half-years
∴
Interest for the first half-year
=
P
R
T
100
=
1000
×
8
×
1
100
×
2
=
R
s
.
40
Amound after one half-year
=
R
s
.1040
or, Principal for the second half-year
=
R
s
.
1040
Interest for the second half-year
=
1040
×
8
×
1
100
×
2
=
R
s
.
4160
100
=
R
s
.
41.60
Amount after second half-year
=
R
s
.
1040
+
41.60
=
R
s
.
1081.6
or, Principal for the third half-year
=
R
s
.
1081.60
Interest for the third half-year
=
1081.60
×
8
×
1
100
×
2
=
R
s
.
4326.40
100
=
R
s
.
43.264
∴
Compound interest for the third half-year
or
1
1
2
years
=
R
s
.
40
+
R
s
.
41.60
+
R
s
.
43.264
=
R
s
.
124.864
Step-by-step explanation:
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Step-by-step explanation:
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Question
Find the compound interest on
R
s
.1000
at the rate of
8
%
per annum for
1
1
2
years when interest is compounded half-yearly?
Solution
Principal (P)
=
R
s
.
1000
Rate (R)
=
8
%
p.a
Period (T)
=
1
1
2
years
=
3 half-years
∴
Interest for the first half-year
=
P
R
T
100
=
1000
×
8
×
1
100
×
2
=
R
s
.
40
amount after one half-year
=
R
s
.1040
or, Principal for the second half-year
=
R
s
.
1040
Interest for the second half-year
=
1040
×
8
×
1
100
×
2
=
R
s
.
4160
100
=
R
s
.
41.60
Amount after second half-year
=
R
s
.
1040
+
41.60
=
R
s
.
1081.6
or, Principal for the third half-year
=
R
s
.
1081.60
Interest for the third half-year
=
1081.60
×
8
×
1
100
×
2
=
R
s
.
4326.40
100
=
R
s
.
43.264
∴
Compound interest for the third half-year
or
1
1
2
years
=
R
s
.
40
+
R
s
.
41.60
+
R
s
.
43.264
=
R
s
.
124.864
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