Question

Find the amount received when Rs 10000 is borrowed for 2 years at 10% p.a on compound interest compounded annually. *​

Answer 1

$Answer:-$

$824.32$

$Step-by-step explanation:$

Principal=Rs.10000 ,Rate=2% per half year,Time=2years=4half-years

$Amount=p(1+R/100)^{t} \\\\10000=(1+2/100)^{4} \\\\10000*102/100*102/100*102/100*102/100\\\\Amount=10824.32\\\\C.I=Amount-principle\\C.I=10824.32-10000\\C.I=824.32$

→Hope this will help you :)

Answer 2

Answer:

Step-by-step explanation:

Principle = 10,000

Rate of interest = 10

Time = 2

Amt = p( 1 + r/100)ⁿ

Amt = 10,000( 1 + 0.10)²

Amt = 25,000(1.10)²

Amt = 25,000 * 1.21

Amt = 30,250