Question

find the amount to be paid at the end of 2 years on ₹2400 at 5% per annum =

A) compounded annunly
B) compounded half yearly

Answer is a) 2646 ₹
B) 2649.15

Answer 1

(A)-
We know that,
A=P (1+R/100)Power of year
A= 2400×(1+5/100)power of 2
A=2400×(21/24) power of 2
A= 2400×441/400
A= 6×441
A = 2646
-------------------------------------
B-
we know that
A=P ×(1+r/200)power of 2n
A=2400×(1+5/200)power of 2×2=4
A=2400 × (41×41×41×41/40×40×40×40)
A=(67818264/25600)
A=2649.15

Answer 2

$\boxed{\boxed{\boxed{\bold{\blue{Solution :\longrightarrow}}}}}$

$\boxed{\boxed{\boxed{\bold{Given,}}}}$

$\bold{P = Rs \: \: 2400}$

$\bold{T = 2 \: \: years}$

$\bold{R = 5\% \: \: p.a.}$

$\bold{A) \: \: Since \: \: compounded \: \: annually}$

$\bold{We \: \: know \: \: that \: }$

$\bold{A = P \times (1 + \frac{R}{100} ) {}^{T}} \\ \\ \: \: \: \: \: = Rs \: \: 2400 \times (1 + \frac{5}{100} ) {}^{2} \\ \\ \: \: \: \: \: = Rs \: \: 2400 \times \frac{105}{100} \times \frac{105}{100} \\ \\ \: \: \: \: \: = Rs \: \: 2646\:\:\bold\red{\boxed{Ans}}$

$\bold{B) \: \: Since \: \: compounded \: \: half \: yearly}$

$\bold{We \: \: know \: \: that }\: \:$

$\bold{A = P \times (1 + \frac{R}{200} ) {}^{2T} }\\ \\ \: \: \: \: \: = Rs \: \: 2400 \times (1 + \frac{5}{200} ) {}^{2 \times 2} \\ \\ \: \: \: \: \: = Rs \: \: 2400 \times ( \frac{205}{200} ) {}^{4} \\ \\ \: \: \: \: \: = Rs \: \: 2400 \times \frac{205}{200} \times \frac{205}{200} \times \frac{205}{200} \times \frac{205}{200} \\ \\ \: \: \: \: \: = Rs \: \: 2649.15\:\:\bold\red{\boxed{Ans}}$

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$\bold\green{\boxed{I \: \: hope \: \: it \: \: will \: \: help \: \: you}}$