Question

find the amount to be paid at the end of 3 years if principle = 5000 rupees at the rate of 6% per annum​

Answer 1

Answer:

Here, Principal (P)=Rs.7,500, Rate (R)=5% p.a, Time (T)=3 years

Simple Interest =

100

P×R×T

=

100

7500×5×3

=Rs.1,125

Now, Amount = Principal + Simple Interest

=7500+1125

=Rs.8,625

Answer 2

$\bf \: \underline{Given} :$ ↴

$\sf \implies Principal = Rs. \: 5000$

$\sf \implies Time = 3 \: years$

$\sf \implies Rate = 6 \: \%$

$\bf \: \underline{To \: find} :$ ↴

$\sf \implies The \: amount \: to \: be \: paid \: after \: 3 \: years.$

$\bf \: \underline{Formulas \: to \: be \: used} :$ ↴

$\sf \implies \boxed{ \red{ \sf \: S.I = \dfrac{Principal \times Rate \times Time }{100} }}$

$\sf \implies \boxed{ \green{ \sf \:Amount = Principal + Simple \: interest }}$

$\bf \: \underline{\underline{Solution}}$

$\sf \: First \: of \: all, we \: have \: to \: find \: the \: simple \: interest.$

$\sf \implies \dfrac{5000 \times 6 \times 3 }{100}$

$\sf \implies \dfrac{50\!\!\!\not0\!\!\!\not0 \times 6 \times 3 }{1\!\!\!\not0\!\!\!\not0}$

$\sf \implies 50 \times 6 \times 3$

$\sf \implies 900$

$\purple{ \sf \implies So, \: simple \: interest = Rs. \: 900}$

$\sf Therefore, the \: amount \: after \: 3 \: years \: will \: be :$

$\sf \implies \sf Principal + Simple \: interest$

$\sf \implies \sf Rs. \: 5000 + Rs. \: 900$

$\sf \implies \sf Rs. \: 5900$

$\underline{ \boxed{ \pink{ \sf \: Hence, amount \: after \: 3 \: years \: will \: be \: Rs. \: 5900.}}}$