Question

Find the amount to be paid at the end of 3 years in each case
a):Principal=Rs.1,200 at 12% p.a
b):Principal=Rs.7,500 at 5%p.a

Answer 1

$<i><b>$Answer :

(a) According to the question,

Principal (P) = Rs 1200

Rate (R) = 12 % p.a.

Time (T) = 3 years

We know that,

Simple interest (S.I) = P×R×T/100

Therefore,

S.I = 1200×12×3/100

= 12 × 12 × 3

= 144 × 3

= Rs 432

Hence,

Amount = Principal + S.I

= 1200 + 432

= Rs 1632

(b) According to the question,

Principal (P) = Rs 7500

Rate (R) = 5 % p.a.

Time (T) = 3 years

We know that,

Simple interest (S.I) = 7500×5×3/100

Therefore

S.I = 75 × 5 × 3

= 75 × 15

= Rs 1125

Hence,

Amount = Principal + S.I

= 7500 + 1125

= $<b>$Rs 8625

$\textsf{Formulas used}$

→ Amount = principle + S.I

→ simple interest = P×R×T/100

Answer 2

For part A refer the attachment above ⚡

Part B

Answer:-

₹ 8625

Step-by-step explanation:-

P = ₹7500

R = 5%

T = 3 years

$\sf{ S.I. = \dfrac{ = P \times R \times T}{100}}$

$\sf{S.I. = \dfrac{7500 \times 5 \times 3}{100} }$

$\sf{S.I. = \dfrac{75 \cancel{00} \times 5 \times 3}{ \cancel{100}}}$

$\sf{S.I. = 75 \times 5 \times 3}$

S.I. = ₹1125

Now, for finding Amount,

A = P + I

A = 7500 + 1125

A = ₹8625

Therefore, Amount paid at the end of 3rd year = ₹8625

Here,

P = Principal

R = Rate

T = Time

S.I. = Simple interest

A = Amount

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