find the amount to be returned if rupees 9000 is borrowed for 2×1/3 years and rate of 6 % per annum compounded annually.
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ANSWER:
P=₹9000
n=2×1/3
R=6%
A=p(1+R/100)n
=9000[1+6/100]2×[1+6/100×1/3]
now cancell [1+6/100×1/3]
after cancelling answer is 1+[2/100×1/1]
=9000×[106/100]2×[1+2/100]
=9×106×106×102÷100
=10314.648
A=₹10314.65
Hence the required amount is ₹10314.65
I hope this answer is helpfull:)
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Answer:
10260
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