Question

find the amount to flow of current when 5 ohms 8 ohms and 12 ohms of resistor connected to three dry cell with 2 volt battery ​

Answer 1

Answer:u didn't mentioned whether they are connected in series or in parallel

Explanation: if it is in series the effective resistance is 5+8+12 ohm i.e 25ohms.

So as i=v/r

I=2/25=0.08a

If in parallel, the effective resistance is

1/r=1/5+1/8+1/12

1/r=24/120+15/120+10/120

1/r=24+15+10/120

1/r=49/120

1/r=0.408ohm

So r =2.44ohms

I=2/2.44=0.81a