Question

find the amount when rupees is 1500 and borrowed rate is 6% and per annual for 3 years​ . find simple interest

Answer 1

AnswEr :

$\bf{\blue{\underline{\underline{\bf{Given\::}}}}}$

• Principal,[P] = Rs.1500
• Time,[n] = 3 years
• Rate,[R] = 6% p.a.

$\bf{\blue{\underline{\underline{\bf{To\:find\::}}}}}$

The amount and Simple Interest.

$\bf{\blue{\underline{\underline{\bf{Explanation\::}}}}}$

Formula use :

$\bf{\boxed{\bf{A=P\bigg(1+\frac{R}{100} \bigg)^{n} }}}}}$

$\mapsto\tt{A=1500\bigg(1+\cancel{\dfrac{6}{100}} \bigg)^{3} }\\\\\\\mapsto\tt{A=1500\bigg(1+\dfrac{3}{50} \bigg)^{3} }\\\\\\\mapsto\tt{A=1500\bigg(\dfrac{50+3}{50} \bigg)^{3} }\\\\\\\mapsto\tt{A=15\cancel{00}\times \dfrac{53}{5\cancel{0}} \times \dfrac{53}{5\cancel{0}} \times \dfrac{53}{50} }}\\\\\\\mapsto\tt{A=\cancel{15}\times \dfrac{53}{\cancel{5}} \times \dfrac{53}{5} \times \dfrac{53}{50} }\\\\\\\mapsto\tt{A=\dfrac{3\times 53\times 53\times53 }{250} }$

$\mapsto\tt{A=\cancel{\dfrac{446631}{250}} }\\\\\\\mapsto\tt{\red{A=Rs.1786.52}}$

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Formula use : (S.I.)

$\mapsto\sf{\pink{Simple\:Interest\:=\dfrac{P*R*T}{100} }}\\\\\\\mapsto\sf{Simple\:Interest\:=\dfrac{15\cancel{00}*6*3}{1\cancel{00}} }}\\\\\\\mapsto\sf{Simple\:Interest\:=Rs.(15*6*3)}\\\\\\\mapsto\sf{\red{Simple\:Interest\:=Rs.270}}$

Thus;

The amount is Rs.1786.52 and the S.I. is Rs.270 .

Answer 2

AnSwER:-

• Amount = 1750

• Simple Interest (S. I.) = 270

GiVeN

• Principal (P) = 1500

• Rate (R) = 6%

• Time (T) = 3 years

To FiNd :-

• Amount (A)

• Simple Interest (SI)

SoLuTioN :-

We know that,

Simple Interest ( SI)

$= > \frac{PRT}{100} \\ \\ = > \frac{1500 \times 6 \times 3}{100} \\ \\ = > 15 \times 6 \times 3 = 270$

Now,

Simple Interest ( S. I.) = 270

We know that,

Amount (A) = Principal (P) + Simple Interest(SI)

Amount (A) = 1500 + 270 = 1770