Math, asked by parupallysrija000, 4 months ago

find the amount whose
51/13%
is Rs.520​

Answers

Answered by abhijayraj7
1

Answer:

Step-by-steWe have the following:

(i)  

47

100

 

=(

47

100

 

×100)% = 47%

(ii)  

9

20

 

=(

9

20

 

×100)% =(9×5)%= 45%

(iii)  

3

8

 

=(

3

8

 

×100)% =(

3×25

2

 

)%=(

75

2

 

)%=37

1

2

 

%

(iv)  

8

125

 

=(

8

125

 

×100)%=(

8×4

5

 

)%=(

32

5

 

)%=6.4%

(v)  

19

500

 

=(

19

500

 

×100)%=(

19

5

 

)%=3.8%

(vi)  

4

15

 

=(

4

15

 

×100)%=(

4×20

3

 

)%=(

80

3

 

)%=26

2

3

 

%

(vii)  

2

3

 

=(

2

3

 

×100)%=(

200

3

 

)%=66

2

3

 

%

(viii) 1

3

5

 

=

8

5

 

=(

8

5

 

×100)%=(8×20)%=160%p explanation:

Answered by AkshayPannu
0

Step-by-step explanation:

let total amount= x

then, According to question

51/13% of x = 520

on solving this equation we get

51/12/100=520/x

3.9/100=520/x

0.03x= 520

x= 520×100/3

17333.33

hope it help you

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