Question

Find the and , where a. = { ∈ ℝ | 2 < 1}

Answer 1

Answer:

Hence, 0≤y<1

Range of f is [0,1)

Step-by-step explanation:

Let y=

1+x

2

x

2

⇒y+x

2

y=x

2

⇒y=x

2

(1−y)

⇒x

2

=

1−y

y

Hence, 0≤y<1

Range of f is [0,1)

⇒x=

1−y

y

Since, x is real

⇒

1−y

y

≥0

⇒

(1−y)

2

y(1−y)

≥0

⇒y(1−y)≥0 and (1−y)

2

>0

⇒0≤y≤1 and −y>−1

⇒0≤y≤1 and y<1