Find the Angels of quadrilateral measures are given as 2:3:6:9
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Answered by
1
hello users ......
we have to find
angles of quadrilateral = ?
given that :
angles are in ratio 2:3:6:9
solution :-
we know that
the sum of angles in a quadrilateral = 360°
let
1 st angle be = 2x
2 nd = 3x
3 rd = 6x
4th = 9x
now ,
sum of these angles = 360°
=> 2x +3x + 6x + 9x = 360°
=> 20x = 360°
=> x = 18
hence ;
1st angle = 2×18 = 36°
2nd = 3× 18 = 54°
3rd = 6×18 = 108°
and
4th = 9 × 18 = 162°
❂❂ hope it helps ❂❂
we have to find
angles of quadrilateral = ?
given that :
angles are in ratio 2:3:6:9
solution :-
we know that
the sum of angles in a quadrilateral = 360°
let
1 st angle be = 2x
2 nd = 3x
3 rd = 6x
4th = 9x
now ,
sum of these angles = 360°
=> 2x +3x + 6x + 9x = 360°
=> 20x = 360°
=> x = 18
hence ;
1st angle = 2×18 = 36°
2nd = 3× 18 = 54°
3rd = 6×18 = 108°
and
4th = 9 × 18 = 162°
❂❂ hope it helps ❂❂
Answered by
0
For this we have the suppose
1st angle as 2x
2nd angle as 3x
3rd angle as 6x
4th angle as 9x
So, 1st+2nd+3rd+4th angle =360° (Sum of all sides of quadrilateral)
2x+3x+6x+9x=360°
5x+15x=360°
20x=360°
x=360°/20
x=18°
Now we know that
1st angle =2x=2(18)=36°
2nd angle=3x=3(18)=54°
3rd angle=6x=6(18)=108°
4th angle=9x=9(18)=162°
I hope it helps you
Plz mark it as brainliest..
Thank you
1st angle as 2x
2nd angle as 3x
3rd angle as 6x
4th angle as 9x
So, 1st+2nd+3rd+4th angle =360° (Sum of all sides of quadrilateral)
2x+3x+6x+9x=360°
5x+15x=360°
20x=360°
x=360°/20
x=18°
Now we know that
1st angle =2x=2(18)=36°
2nd angle=3x=3(18)=54°
3rd angle=6x=6(18)=108°
4th angle=9x=9(18)=162°
I hope it helps you
Plz mark it as brainliest..
Thank you
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