find the angle 1 , angle 2, angle 3, angle 4, angle 5, given that angle 3= angle 4
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\angle 1+\angle 2+\angle 3+\angle 4+\angle 5=540^{\circ}
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We have to find the value of \angle 1+\angle 2+\angle 3+\angle 4+\angle 5.
In the given figure ∠1, ∠2, ∠3, ∠4, and ∠5 are interior angles of a pentagon.
Sum of interior angles = ∠1 + ∠2 + ∠3 + ∠4 + ∠5
Sum of interior angles of a polygon is
Sum=(n-2)\times 180^{\circ}
where, n is the number of vertices.
In the figure ABCDE, the number of vertices is 5.
Substitute n=5 in the above formula.
Sum=(5-2)\times 180^{\circ}
Sum=3\times 180^{\circ}
Sum=540^{\circ}
Therefore, the value of \angle 1+\angle 2+\angle 3+\angle 4+\angle 5 is 540°.
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