Find the angle a b and c
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Answer:
Angle BAC = 60°
Angle ABC = 52°
Angle ACB = 68°.
Explanation:
1) Angle BAC + Angle BAE = 180 (Angles in a linear pair )
Therefore,
Angle BAC + 120° = 180 °
Angle BAC = 180 - 120 = 60
Therefore,
Angle BAC = 60°
2) Angle ACB + Angle ACD = 180 (Angles in a linear pair )
Therefore,
Angle ACB + 112° = 180°
Angle ACB = 180 - 112 = 68°
Therefore,
Angle ACB = 68°
3) Angle ACB + Angle BAC + Angle ABC = 180 (Angle sum property of a triangle)
Therefore,
68° + 60° + Angle ABC = 180°
128 + Angle ABC = 180
Angle ABC = 180 - 128 = 52
Therefore,
Angle ABC = 52°
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