Find the angle at which a ball must be projected so that it just passes over a pole 10 m high and at a distance of 20 m from the point of projection
Answers
Answer:
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Answer:
The correct answer to this question is
the angle of projection θ = 26.565
Explanation:
Angle of projection:
the angle of projection is the angle between the surface and the object which is to be projected.
Let,
the height of the pole AB = 10 m
the distance from the foot of the pole to the point of projection of the ball AC = 20 m
we can form an angle at C, which is the angle of projection.
given the ball must be projected and needed to just pass over the pole.
from the above statement, we can get a closed triangle figure and
∠ACB is to be determined.
From triangle ABC,
AB = 10 m
BC = 20 m
Let, ∠ACB = θ
from Tan θ = opposite side / adjacent side
Tan θ = AB / BC
Tan θ = 10 / 20
Tan θ = 1 / 2
θ = Tan⁻¹( 1/2 )
θ = Tan⁻¹( 0.5 )
θ = 26.565 (approximately)
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