find the angle betueen the lines 3x-y+2=0 and x-2y+3=0
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Letm, & m₂ be the slopes of straight lines. x - 2y + 3 = 0 and 3x + y - 1 = 0 .
Then, m_{1} = - 1/- 2 = 1/2 and m_{2} = - 3/1 = - 3
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Le + theta be the angle b/w the given lines. The
tan theta=| m 1 -m 2 1+m 1 m 2 |= 1 2 +3 1- 3 2 |=7
theta = tan^7 (7)
Hence, abtuseangle = 7 - tan^1 (7) .
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