Question

find the angle between 0° abd 360°, which satisfies the equation sin²theta=3/2​

Answer 1

Answer:

43° & 137°

Step-by-step explanation:

Sin x= Cos 47°

as we know that

Sinx° = cos (90°-x°)

so applying the same

Cos(90°-x°) = Cos 47°

=> 90°-x° = 47°

=> -x° = 47° - 90°

=> -x° = -43°

=> x = 43°  

as we also know that

Sinx° = Sin(180° -x°)

putting value of x

Sinx° = Sin(180°-43°)

Sinx° = Sin137°

$\bf\:x = 137°$

Answer 2

Answer:

43° & 137°

Step-by-step explanation:

Sin x= Cos 47°

as we know that

Sinx° = cos (90°-x°)

so applying the same

Cos(90°-x°) = Cos 47°

=> 90°-x° = 47°

=> -x° = 47° - 90°

=> -x° = -43°

=> x = 43°

as we also know that

Sinx° = Sin(180° -x°)

putting value of x

Sinx° = Sin(180°-43°)

Sinx° = Sin137°

\bf\:x = 137°x=137°