Physics, asked by pawarasachin25, 9 months ago

Find the angle between a and b; a=2i+j-k,b=i-k

Answers

Answered by abhijeetdasskrillex
0

Explanation:

We're asked to find the angle between two vectors, given their unit vector notations.

To do this, we can use the equation

A

B

=

A

B

cos

θ

rearranging to solve for angle,

θ

:

cos

θ

=

A

B

A

B

θ

=

arccos

A

B

A

B

where

A

B

is the dot product of the two vectors, which is

A

B

=

A

x

B

x

+

A

y

B

y

+

A

z

B

z

=

(

2

)

(

1

)

+

(

3

)

(

2

)

+

(

1

)

(

4

)

=

4

A

and

B

are the magnitudes of vectors

A

and

B

, which are

A

=

2

2

+

3

2

+

1

2

=

14

B

=

1

2

+

2

2

+

(

4

)

2

=

21

Therefore, we have

θ

=

arccos

(

4

14

21

)

=

arccos

(

4

7

6

)

=

76.5

o

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