Find the angle between A and B vector .
A = 4i^ and B = (-3 i^ + 3 j^ )
need step .
ans= 135 °
Attachments:
Answers
Answered by
12
Hope this helps you ☺☺
Attachments:
Anonymous:
thanks for brainliest
Answered by
19
vector A=4i^
B=(-3i^+3j^)
now angle is cos theta=(A.B)/|A|×|B|
=(-12)/4×3root2=-1/root2=cos 135°
hence angle is 135°
B=(-3i^+3j^)
now angle is cos theta=(A.B)/|A|×|B|
=(-12)/4×3root2=-1/root2=cos 135°
hence angle is 135°
Similar questions