find the angle between (a⃗+b⃗) and (A⃗.B⃗) in vector?
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Answer:
Step-by-step explanation:
It is given that,
∣
a
∣=
3
,
∣
∣
∣
∣
b
∣
∣
∣
∣
=2 and,
a
⋅
b
=
6
Now, we know that
a
⋅
b
=∣
a
∣∣
b
∣cosθ
∴
6
=
3
×2×cosθ
⇒cosθ=
3
×2
6
⇒cosθ=
2
1
⇒θ=
4
π
Hence, the angle between the given vectors
a
and
b
is
4
π
.
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