Find the angle between A vector=2icap -4jcap+6kcap and 3i cap +jcap +2k cap
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Angle between them is 60
As the dot product
A.B=|A|.|B|cosθ
14=( root56xroot14)xcosθ
14=28cosθ
cosθ=1/2
θ=60
As the dot product
A.B=|A|.|B|cosθ
14=( root56xroot14)xcosθ
14=28cosθ
cosθ=1/2
θ=60
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