find the angle between circles x^2+y^2=a^2 and x^2+y^2=ax+ay
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Answer:
135°
Step-by-step explanation:
Concept= Angle between Circle
Given= Equations of two Circle
To Find= Angle between two circle
Explanation=
We have been given the equation of two circles as x^2+y^2=a^2 and x^2+y^2=ax+ay.
We take two circle as S1 and S2
S1= x^2+y^2=a^2
=> x^2+y^2-a^2 =0
Centre of S1 is c1=(0,0)
Radius of S1 is r1 = a
S2= x^2+y^2-ax-ay=0
Centre of S2 is c2= (a/2 , a/2)
Radius of S2 is r2= (a/√2)
Difference in center is d which is √(a/2)²+(a/2)² = a/√2
Therefore the angle Ф will be cosФ= (d²-r1²-r2²)/2r1r2
=>((a/√2)² - a² - (a/√2)²)/2aa/√2 = -1/√2
cosФ= cos135°
Ф=135°
Therefore the angle between two circle x^2+y^2=a^2 and x^2+y^2=ax+ay is 135°
#SPJ2
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