Find the angle between curves f(x) = 2' log x and
g(x) = x2x - 1.
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Answer:
f(x)=2
x
log
e
x,g(x)=x
2x
−1
f
1
(x)=
x
2
x
+logx.2
x
ln2 , g
1
(x)=x
2x
(2
2
1
+ln2x)
As, f(x) & g(x) meets at x=1
f
1
(1)=2(m
1
),g
1
(1)=1+ln2(m
2
)
tanθ=
1+m
1
m
2
m
1
−m
2
=
1+2(1+ln2)
2−(1+ln2)
=
3+ln2
1−ln2
⇒cosθ=0.99
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